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B1 中級 英語 22:20 Educational

Taylor series | Chapter 11, Essence of calculus

3Blue1Brown · 4,895,032 回視聴 · 追加日 2ヶ月前

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00:14

When I first learned about Taylor series, I definitely

00:17

didn't appreciate just how important they are.

00:20

But time and time again they come up in math, physics,

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and many fields of engineering because they're one of the most

00:25

powerful tools that math has to offer for approximating functions.

00:30

I think one of the first times this clicked for me as a

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student was not in a calculus class but a physics class.

00:35

We were studying a certain problem that had to do with the potential energy of a

00:40

pendulum, and for that you need an expression for how high the weight of the

00:44

pendulum is above its lowest point, and when you work that out it comes out to be

00:48

proportional to 1 minus the cosine of the angle between the pendulum and the vertical.

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The specifics of the problem we were trying to solve are beyond the point here,

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but what I'll say is that this cosine function made the problem awkward and unwieldy,

01:02

and made it less clear how pendulums relate to other oscillating phenomena.

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But if you approximate cosine of theta as 1 minus theta squared over 2,

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everything just fell into place much more easily.

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If you've never seen anything like this before,

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an approximation like that might seem completely out of left field.

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If you graph cosine of theta along with this function, 1 minus theta squared over 2,

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they do seem rather close to each other, at least for small angles near 0,

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but how would you even think to make this approximation,

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and how would you find that particular quadratic?

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The study of Taylor series is largely about taking non-polynomial

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functions and finding polynomials that approximate them near some input.

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The motive here is that polynomials tend to be much easier to deal

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with than other functions, they're easier to compute,

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easier to take derivatives, easier to integrate, just all around more friendly.

02:00

So let's take a look at that function, cosine of x,

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and really take a moment to think about how you might construct a quadratic

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approximation near x equals 0.

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That is, among all of the possible polynomials that look like c0 plus c1

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times x plus c2 times x squared, for some choice of these constants, c0,

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c1, and c2, find the one that most resembles cosine of x near x equals 0,

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whose graph kind of spoons with the graph of cosine x at that point.

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Well, first of all, at the input 0, the value of cosine of x is 1,

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so if our approximation is going to be any good at all,

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it should also equal 1 at the input x equals 0.

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Plugging in 0 just results in whatever c0 is, so we can set that equal to 1.

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This leaves us free to choose constants c1 and c2 to make this

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approximation as good as we can, but nothing we do with them is

03:00

going to change the fact that the polynomial equals 1 at x equals 0.

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It would also be good if our approximation had the same

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tangent slope as cosine x at this point of interest.

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Otherwise the approximation drifts away from the

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cosine graph much faster than it needs to.

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The derivative of cosine is negative sine, and at x equals 0,

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that equals 0, meaning the tangent line is perfectly flat.

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On the other hand, when you work out the derivative of our quadratic,

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you get c1 plus 2 times c2 times x.

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At x equals 0, this just equals whatever we choose for c1.

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So this constant c1 has complete control over the

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derivative of our approximation around x equals 0.

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Setting it equal to 0 ensures that our approximation

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also has a flat tangent line at this point.

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This leaves us free to change c2, but the value and the slope of our

03:57

polynomial at x equals 0 are locked in place to match that of cosine.

04:04

The final thing to take advantage of is the fact that the cosine graph

04:08

curves downward above x equals 0, it has a negative second derivative.

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