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B1 中级 英语 13:50 Educational

What's so special about Euler's number e? | Chapter 5, Essence of calculus

3Blue1Brown · 4,949,832 次观看 · 添加于 3 周前

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00:14

I've introduced a few derivative formulas, but a

00:17

really important one that I left out was exponentials.

00:20

So here I want to talk about the derivatives of functions like 2 to the x, 7 to the x,

00:26

and also to show why e to the x is arguably the most important of the exponentials.

00:32

First of all, to get an intuition, let's just focus on the function 2 to the x.

00:36

Let's think of that input as a time, t, maybe in days, and the output,

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2 to the t, as a population size, perhaps of a particularly

00:45

fertile band of pie creatures which doubles every single day.

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And actually, instead of population size, which grows in discrete little jumps with each

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new baby pie creature, maybe let's think of 2 to the t as the total mass of the

01:00

population.

01:02

I think that better reflects the continuity of this function, don't you?

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So for example, at time t equals 0, the total mass is 2 to the 0 equals 1,

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for the mass of one creature.

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At t equals 1 day, the population has grown to 2 to the 1 equals 2 creature masses.

01:21

At day t equals 2, it's t squared, or 4, and in general it just keeps doubling every day.

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For the derivative, we want dm dt, the rate at which this population mass is growing,

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thought of as a tiny change in the mass, divided by a tiny change in time.

01:39

Let's start by thinking of the rate of change over a full day,

01:44

say between day 3 and day 4.

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In this case, it grows from 8 to 16, so that's 8

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new creature masses added over the course of one day.

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And notice, that rate of growth equals the population size at the start of the day.

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Between day 4 and day 5, it grows from 16 to 32,

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so that's a rate of 16 new creature masses per day,

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which again equals the population size at the start of the day.

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And in general, this rate of growth over a full day

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equals the population size at the start of that day.

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So it might be tempting to say that this means the derivative

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of 2 to the t equals itself, that the rate of change of this

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function at a given time t is equal to the value of that function.

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And this is definitely in the right direction, but it's not quite correct.

02:39

What we're doing here is making comparisons over a full day,

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considering the difference between 2 to the t plus 1 and 2 to the t.

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But for the derivative, we need to ask what happens for smaller and smaller changes.

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What's the growth over the course of a tenth of a day,

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a hundredth of a day, one one billionth of a day?

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